111213
1 1 12 13 = 24: 18 solutions
Difficulty: HardOpen in Solver
12 + 13 − 1 × 1 = 24
- 12 + 13 = 25
- 1 × 1 = 1
- 25 − 1 = 24
18 solutions
12 + 13 − 1 ÷ 1 = 24Steps
- 12 + 13 = 25
- 1 ÷ 1 = 1
- 25 − 1 = 24
1 × 13 − (1 − 12) = 24Steps
- 1 × 13 = 13
- 1 − 12 = -11
- 13 − -11 = 24
13 − 1 × (1 − 12) = 24Steps
- 1 − 12 = -11
- 1 × -11 = -11
- 13 − -11 = 24
13 ÷ 1 − (1 − 12) = 24Steps
- 13 ÷ 1 = 13
- 1 − 12 = -11
- 13 − -11 = 24
13 − (1 − 12) ÷ 1 = 24Steps
- 1 − 12 = -11
- -11 ÷ 1 = -11
- 13 − -11 = 24
1 × 12 − (1 − 13) = 24Steps
- 1 × 12 = 12
- 1 − 13 = -12
- 12 − -12 = 24
12 − 1 × (1 − 13) = 24Steps
- 1 − 13 = -12
- 1 × -12 = -12
- 12 − -12 = 24
12 ÷ 1 − (1 − 13) = 24Steps
- 12 ÷ 1 = 12
- 1 − 13 = -12
- 12 − -12 = 24
12 − (1 − 13) ÷ 1 = 24Steps
- 1 − 13 = -12
- -12 ÷ 1 = -12
- 12 − -12 = 24
13 + 1 × (12 − 1) = 24Steps
- 12 − 1 = 11
- 1 × 11 = 11
- 13 + 11 = 24
13 + (12 − 1) ÷ 1 = 24Steps
- 12 − 1 = 11
- 11 ÷ 1 = 11
- 13 + 11 = 24
1 × (12 + 13) − 1 = 24Steps
- 12 + 13 = 25
- 1 × 25 = 25
- 25 − 1 = 24
(12 + 13) ÷ 1 − 1 = 24Steps
- 12 + 13 = 25
- 25 ÷ 1 = 25
- 25 − 1 = 24
12 + 1 × (13 − 1) = 24Steps
- 13 − 1 = 12
- 1 × 12 = 12
- 12 + 12 = 24
12 + (13 − 1) ÷ 1 = 24Steps
- 13 − 1 = 12
- 12 ÷ 1 = 12
- 12 + 12 = 24
1 × (13 − (1 − 12)) = 24Steps
- 1 − 12 = -11
- 13 − -11 = 24
- 1 × 24 = 24
(13 − (1 − 12)) ÷ 1 = 24Steps
- 1 − 12 = -11
- 13 − -11 = 24
- 24 ÷ 1 = 24
Solving hints
Build a factor pair: split the four numbers into two groups and try to make a factor pair of 24 — 3 × 8, 4 × 6, or 12 × 2 — then multiply the two groups.
No factor pair divides cleanly? Switch to sums: make two numbers add up to 24, or try shapes like (a ± b) × (c ± d) and (a + b + c) × d.
Related hands
FAQ
Can 1 1 12 13 make 24?
Yes. Every one of them is listed above with step-by-step working.
How many solutions does 1 1 12 13 have?
18 — the list above is exhaustive, so every mathematically distinct way to combine the numbers is shown.
How difficult is 1 1 12 13?
It is rated “Hard” on our four-tier scale, based on whether whole-number intermediate steps suffice, how many distinct solutions exist, and whether the hand includes a two-digit card (10–13).